Boost Users :
Subject: [Boost-users] What result_type ? And why?
From: John M. Dlugosz (mpbecey7gu_at_[hidden])
Date: 2011-07-19 02:16:11
I wrote the following functor:
template< typename CharT >
CharT operator() (const CharT& ch) const
if (ch >= 'A' && ch <= 'Z') return ch+0x20;
return ch; // unchanged
and when I used it to create a transformed_range, I get an error that it doesn't find
result_type in ASCII_lower.
Since the return type depends on the argument, how could I declare a result_type?
And why do I need it? Lambda functions don't have it, and I thought it was fairly old
fashioned and optional for helping figure out the result type if necessary.
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