Re: [Boost-users] begin (cout) or boost::copy to cout

Subject: Re: [Boost-users] begin (cout) or boost::copy to cout
From: Nathan Ridge (zeratul976_at_[hidden])
Date: 2011-09-14 00:29:32

>>> This function eliminats the need of passing explicit template parameters to 
>>> std:: ostream_iterator, which makes the code fragile and hard to read.
>> 
>> I agree that having to pass a template parameter to std::ostream_iterator
>> is annoying.
>> 
>> ...
>> 
>> A better solution is to write a polymorphic version of ostream_iterator;
>> that is, a version that's not a template, but which has a templated
>> operator=, so that you can output any type using the iterator.
>> 
> I suspect that it would be difficult to
> make a valid STL iterator like that.
> How would you define std::iterator_traits
> for it?
 
ostream_iterator already has "void" as its value_type, difference_type, pointer,
and reference (and so do other standard output iterators like insert_iterator)...
so there would be no difference between the standard version and the modified
version in that regard.

Regards,
Nate