Re: [Boost-users] math tools roots

Subject: Re: [Boost-users] math tools roots
From: Jerry (jerry_jeremiah_at_[hidden])
Date: 2011-10-10 16:51:32

<curtis2006 <at> mac.com> writes:
> 
> I haven't been following this thread closely, but I know enough math to say
> that lim_{x->0} (0/x) is 0.
> When evaluating a limit, one does not simply substitute the limiting value
> into the expression. Â The limit is the value of the expression as the
> variable gets arbitrarily close but not equal to the limiting value.  As x
> gets arbitrarily close to 0, 0/x remains exactly 0. Â I have no clue, how
> this impacts the original issue.
> 
> Cheers.
> 
> Curtis Gehman
> Burlingame, CA
> 

Another way of looking at it is to use L'Hopital's rule:

lim_{x->0} ((x-x)/min(|x|,|x|)) => lim_{x->0} ((x-x)/x)
                                => d/dx(x-x) / d/dx(x)
                                => (1-1) / 1
                                => 0

Like Curtis says, no idea exactly what that means for the original question.

Jerry