[Boost-users] [lambda] Using a reference in an expression

Subject: [Boost-users] [lambda] Using a reference in an expression
From: Bill Buklis (boostusr_at_[hidden])
Date: 2012-09-12 15:14:06

How does one use a reference in a lambda expression? The documentation 
says that "var" does, but it clearly doesn't.

For example this fails to compile because it can't access the copy 
constructor:

#include <boost/lambda.hpp>
namespace bll = boost::lambda;

class sample
{
public:
     sample()
     {
     }
     sample& operator<<( int )
     {
         return(*this);
     }

private:
     sample( const sample& );
};

void test()
{
     typedef std::vector<int>    V;

     V        v;
     sample    s;

     std::for_each(v.begin(), v.end(), bll::var(s) << bll::_1);
};

-- 
Bill