Re: [Boost-users] dynamic_bitset get block_type not ulong

Subject: Re: [Boost-users] dynamic_bitset get block_type not ulong
From: Michael Powell (mwpowellhtx_at_[hidden])
Date: 2013-04-04 19:01:03

On Thu, Apr 4, 2013 at 8:32 AM, Michael Powell <mwpowellhtx_at_[hidden]>wrote:

Another question, perhaps to clarify my misunderstanding how dynamic_bitset
operates:

On line 109 of dynamic_bitset.hpp, it would appear that it's dealing with
m_block as a reference. In other words, dynamic_bitset is a view on an
existing variable. Which is fine, that's perfect actually. That gets me
closer to where I'd like to be and means I don't have to chase vectors of
bytes for the result.

Does that mean we use it something like this:

unsigned char my_data;
boost::dynamic_bitset<unsigned char> my_bitset(my_data);
//Twiddle some bits...
//Run with the my_data answer...

Is that accurate or am I still misunderstanding? Thank you...

> On Thu, Apr 4, 2013 at 8:22 AM, Michael Powell <mwpowellhtx_at_[hidden]>wrote:
>
>> Hello,
>>
>> How do I get at the block_type value itself, not an unsigned long, from a
>> dynamic_bitset (or std::bitset for that matter).
>>
>
> The best candidate I've found thus far is:
> http://stackoverflow.com/questions/8297913/how-do-i-convert-bitset-to-array-of-bytes-uint8
>
> 'Course, then there's the argument, is that too much abstraction around
> what is basically a "simple" bit-field bit-mask I want to accomplish.
>
>
>> For instance, can I do something like this?
>>
>> typedef unsigned char byte;
>> boost::dynamic_bitset<byte> my_bitset(static_cast<byte>(0x00));
>> //Do some bit twiddling...
>> byte my_value = static_cast<byte>(my_bitset);
>>
>> Or something like that. Basically I want to avoid any to_ulong() mumbo
>> jumbo if I can just get at the underlying block_type value.
>>
>> Thank you...
>>
>> Regards,
>>
>> Michael Powell
>>
>
>