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Subject: Re: [Boost-users] calc2_ast.cpp
From: Olivier Austina (olivier.austina_at_[hidden])
Date: 2013-10-03 08:28:11
Thank you Larry.
Regards
Olivier
2013/10/2 Larry Evans <cppljevans_at_[hidden]>
> On 10/02/13 12:13, Olivier Austina wrote:
>
>> Hi,
>> this is a basic question (I am sorry).
>> I am try to undestand the calc2_ast.cpp example at
>> http://www.boost.org/doc/libs/**1_41_0/libs/spirit/example/qi/**
>> calc2_ast.cpp<http://www.boost.org/doc/libs/1_41_0/libs/spirit/example/qi/calc2_ast.cpp>
>> I think the instruction expression_ast() : expr(nil()){} is an
>> inheritance.
>>
> expr is a member variable of expression_ast.
>
>> Where can I find the definition of expr()?
>>
> See below.
>
>> This is the code
>> struct expression_ast
>> {
>> typedef
>> boost::variant<
>> nil // can't happen!
>> , unsigned int
>> , boost::recursive_wrapper<**expression_ast>
>> , boost::recursive_wrapper<**binary_op>
>> , boost::recursive_wrapper<**unary_op>
>> >
>> type;
>>
>> *expression_ast() : expr(nil()){};*
>>
>> template <typename Expr>
>> expression_ast(Expr const& expr)
>> : expr(expr) {}
>>
>> expression_ast& operator+=(expression_ast const& rhs);
>> expression_ast& operator-=(expression_ast const& rhs);
>> expression_ast& operator*=(expression_ast const& rhs);
>> expression_ast& operator/=(expression_ast const& rhs);
>>
>> type expr;
>>
> Here's the definition of expr.
>
>> };
>>
>> //expression_ast bbb;
>> struct binary_op
>> {
>> binary_op(
>> char op
>> , expression_ast const& left
>> , expression_ast const& right)
>> : op(op), left(left), right(right) {}
>>
>> char op;
>> expression_ast left;
>> expression_ast right;
>> };
>>
>>
>> Thank you.
>>
>>
>>
>> Regards
>> Olivier
>>
>>
>>
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>>
>>
>
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