Re: [Boost-users] Converting Timestamp into hex of 8 bytes

Subject: Re: [Boost-users] Converting Timestamp into hex of 8 bytes
From: Kulti (kultihell_at_[hidden])
Date: 2013-11-09 00:55:44

How you can store 10 digits to 8 chars? Probably you mean "char
TIMESTAMP[10]" or "char TIMESTAMP[11]" (because you need a null-terminated
symbol for c-strings). So if you have not a c-string, but just array with
digit's symbols - I suggest you to write simple convert function like this

int number = 0;
for (int i = 0; i < num_of_digits; ++i) {
  number = number*10 + TIMESTAMP[i];
}

In case with c-strings use Igor R solution.

On Fri, Nov 8, 2013 at 7:54 PM, Rahul Mathur <srivmuk_at_[hidden]> wrote:

> YES, do have the TIMESTAMP from string viz 1383889129. Since, the
> declaration of TIMESTAMP is "char TIMESTAMP[8]", so looking how to convert
> this?
>
>
> On Fri, Nov 8, 2013 at 11:49 AM, Igor R <boost.lists_at_[hidden]> wrote:
>
>> > I have a string Timestamp of 1383889129 which on ONLINE conversion from
>> > string to hex gives a 10 bytes as "31 33 38 33 38 38 39 31 32 39".
>>
>> The above is not "conversion from string to hex", but merely a hex
>> representation of every ascii character in "1383889129" string.
>>
>>
>> > But, the need is to have the TIMEStamp in 8 bytes only.
>>
>> It's unclear what you want exactly. If you need a time-stamp as a
>> number, use boost::lexical_cast<int>("1383889129") or any other
>> ascii-to-int conversion.
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