Re: [Boost-users] [boost.msm] BOOST_MSM_EUML_DECLARE_STATE_MACHINE with state base class

Subject: Re: [Boost-users] [boost.msm] BOOST_MSM_EUML_DECLARE_STATE_MACHINE with state base class
From: Stefan Näwe (stefan.naewe_at_[hidden])
Date: 2014-05-26 02:29:08

Am 25.05.2014 21:19, schrieb Christophe Henry:
>> [...]
>> But now I want to add the state base class to the
>> above invocation of BOOST_MSM_EUML_DECLARE_STATE_MACHINE to be
>> able to say :
>>
>>    fsm.get_state_by_id(fsm.current_state()[0])->work()
>>
>> at any given time.
>>
>> BOOST_MSM_EUML_DECLARE_STATE_MACHINE((
>> trans_table,
>> init_ << Running,
>> no_action,  // fsm_entry
>> no_action,  // fsm_exit
>> attributes_ << one_attr << another_attr,
>> configure_  << no_configure_,
>> Log_No_Transition,
>> Log_Exception,
>> Worker),
>>  MyFSM_fe)
>>
>> But this gives me a compile error:
>>
>>   C2275: 'Worker' : illegal use of this type as an expression.
>>
>> Is there any way to achieve what I need ? Can I somehow
>> _NOT_ use the macro and create the same state machine (i.e. with
>> attributes!) ?
>>
>> Thanks for any help!
>>
>> Stefan
> 
> 
> Hi,
> I just tried it out. Worker is a type and we need an instance in 
> BOOST_MSM_EUML_DECLARE_STATE_MACHINE, so it should be:
> ...
> Log_Exception,
> Worker()),
> MyFSM_fe)
> 
> 
> Unfortunately it would not compile because of the pure virtual. At the 
> moment I'm afraid we have to live with the limitation of having a simple 
> virtual work().

OK.

Meanwhile I thought about using an internal transition to achieve
what I need.

Thanks,
  Stefan
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