[Boost-users] boost variant is not a literal type

Subject: [Boost-users] boost variant is not a literal type
From: Robert Ramey (ramey_at_[hidden])
Date: 2016-01-06 15:52:28

I want to use Boost.Variant constexpr function. In order to do this it 
has to be a literal type - which apparently it isn't.  The rule for 
being a literal type are summarized here:

http://en.cppreference.com/w/cpp/concept/LiteralType

a boost::variant isn't default constructable so it fails to qualify.

Has anyone else had this problem before and managed to solve it in a 
convenient way?

Robert Ramey