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Subject: [Boost-users] [proto] grammar to match operator in expression
From: Igor R (boost.lists_at_[hidden])
Date: 2016-05-16 12:44:32


Hi,

Why the following grammar doesn't match dereference, and what's the
correct way to do this?

Thanks!

//////////////////
#include <iostream>
#include <boost/proto/proto.hpp>

namespace proto = boost::proto;
using proto::_;

struct has_deref : proto::or_<
    proto::dereference<_>,
    proto::nary_expr<_, proto::vararg<has_deref>>
>
{};

template<class Expr>
void test_expr(const Expr &e)
{
    proto::display_expr(e);
    std::cout << "matches? " << std::boolalpha << proto::matches<Expr,
has_deref>::value << std::endl;
}

int main()
{
    test_expr(proto::lit(1) + *proto::lit(2));
}


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