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Subject: [Boost-users] [Fusion] wide-char output
From: Leo Cacciari (leo.cacciari_at_[hidden])
Date: 2017-04-05 15:10:56
Hi,
the documentation of the Boost.Fusion library (1.63.0) at
http://www.boost.org/doc/libs/1_63_0/libs/fusion/doc/html/fusion/sequence/operator/i_o/out.html
affirms that operator<< is defined in the boost::fusion namespace with
the following synopsis:
template <typename OStream, typename Sequence>
OStream&
operator<<(OStream& os, Sequence& seq);
where the template parameter OStream is defined as "An output stream".
Accordingly, I thought that the following would work:
using boost::fusion::operator<<;
fusion::vector<int, double, const char *> v =
fusion::make_vector(42, 3.1415, "foobar");
std::wcout << "v = " << v << std::endl;
However, the compiler (MSVC 9) complains that it has:
"found no defined operator << taking a right-hand argument of type
boost::fusion::vector<T0,T1,T2> with T0 = int, T1 = double, T2 = char
*"
If I replace std::wcout with its narrow-char sibling std::cout,
everything works as expected; i.e. the code compiles and when run
prints (42,3.1415, foobar).
Looking into the source (file boost/fusion/sequence/io/out.hpp) it
seems that the operator<< is only defined for left-hand argument of
type std::ostream.
Thus the questions:
1. Is this a bug and should I post a ticket about it? (I looked in
the bugs database but I couldn't find it)
2. If it's a bug, are there any plan to patch it soon?
3. If not, does exist any reason why it shouldn't be patched nevertheless?
If needed, I could volunteer for writing a patch.
Thank for your attention
-- Leo Cacciari Aliae nationes servitutem pati possunt. Populi Romani est propria libertas.
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