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Subject: [Boost-users] boost::units - converting from one derived_dimension to another across systems (imperial to metric)
From: Matt Vinson (matt.vinson_at_[hidden])
Date: 2018-11-21 03:55:29


 Michael Powell:
A) I hope to get Boost.Units to convert all these for me.  I am replacing my own unit conversion classes with Boost.Units so there are no masking certain details, magic numbers, etc!  Fingers Crossed.
B) Boost.Units looks promising.  Good to hear it has strong support.  I'll keep at it.  Thanks!//
Steven Watanabe: Got it!  You've been very patient and awesome.  Thank you, yet again.I updated to this because I do need mass for density conversions:typedef boost::units::make_system<
boost::units::us::inch_base_unit,
boost::units::us::pound_base_unit,
boost::units::us::pound_force_base_unit
 >::type
ip_system;
Any issues you see with boost::units::us::pound_base_unit for mass && boost::units::us::pound_force_base_unit for force?  If I don't hear from you, I'll presume it's okay.
My density unit testing* still passed after adding boost::units::us::pound_force_base_unit so I don't think there are issues.

*each of these are converted to the other.
enum class DENSITY : char
{
    K_FT3 = 0,
    K_IN3 = 1,
    LB_FT3 = 2,
    LB_IN3 = 3,
    MT_M3 = 4,
    MT_CM3 = 5,
    MT_MM3 = 6,
    KG_M3 = 7,
    KG_CM3 = 8,
    KG_MM3 = 9,
    LAST = 10
};

    On Tuesday, November 20, 2018, 9:09:45 PM CST, boost-users-request_at_[hidden] <boost-users-request_at_[hidden]> wrote:
 
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Today's Topics:

  1. Re: boost::units - converting from one derived_dimension to
      another across systems (imperial to metric) (Michael Powell)
  2. Re: Program Options documentation is anaemic (Gavin Lambert)
  3. Re: boost::units - converting from one derived_dimension to
      another across systems (imperial to metric) (Steven Watanabe)
  4. Re: Enquiry on boost.geometry and intersection() (Adam Wulkiewicz)

----------------------------------------------------------------------

Message: 1
Date: Tue, 20 Nov 2018 20:55:19 -0500
From: Michael Powell <mwpowellhtx_at_[hidden]>
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] boost::units - converting from one
    derived_dimension to another across systems (imperial to metric)
Message-ID:
    <CAMEoF_GFTg_Fx4haDdb2i65fEaOB_hnG8QmrgshMSG5-0XT5mQ_at_[hidden]>
Content-Type: text/plain; charset="UTF-8"

On Tue, Nov 20, 2018 at 8:47 PM Matt Vinson via Boost-users
<boost-users_at_[hidden]> wrote:
>
> degski: I do not think am making the "nauseam" mistake.  My issue is using Boost.Units correctly which I concede is difficult for me but I am reading the docs and trying to get it.
> In our field of engineering, we use Kg as a force; not a mass.  (We also use pound as a force; not a mass - for your "UK's Weights and Measures Act 1963" counterpart).  That said, I should not have made the mistake of using Kg as a force in Boost.Units, it's true.  Shame on me.
> My task is to convert between lineal forces: k/ft, k/in, lb/ft, lb/in, kN/m, kN/cm, kN/m, N/m, N/cm, N/m, Metric ton/m, Metric ton/cm, Metric ton/mm, Kg/m, Kg/cm, Kg/mm.  These are all force/length.

Coming from an energy oil and gas background applying Boost.Units,
that's a difficult conversation to have especially when "units" are
used, but in fact are masking certain details, magic numbers, etc,
confounding their dimensions.

> Steven Watanabe: Thank you, again.
> #1: I was not trying to say it's wrong; sorry.  Just that I did not see 'length' and opted for the one that did.  The unit's are correct, as you say.
> #2: This is an error to start with Kg(force)/meter.  I can start with N/meter.  I've changed this variable name to newton_per_meter and the conversion factors.

I can tell you this much; once you get reasonably proficient with
Boost.Units, there is a strong compiler confidence in correctness once
you have your dimensions, units, etc, meshing well together. By that I
mean, in truth, compile time confidence. The compiler / Boost.Units
will tell you when you have it wrong, and it will compile when you
have it correct. That's a major plus in my book.

Cheers, best of luck!

> *.h-----------------------------------------------------
>
> namespace dimensional_analysis {
>
>    typedef boost::units::length_base_dimension::dimension_type length_dimension;
>
>    typedef boost::units::mass_base_dimension::dimension_type mass_dimension;
>
> typedef boost::units::make_system<boost::units::us::inch_base_unit,boost::units::us::pound_base_unit>::type ip_system;
>
>        namespace lineal_force {
>
>              typedef boost::mpl::divides<boost::units::force_dimension,boost::units::length_dimension>::type lineal_force_dimension;
>
>              namespace imperial {
>
>                      ////////////////
>
>                      ////lb/in, right?
>
> ////boost::units::force_dimension = pound
>
> ////boost::units::length_dimension = in
>
>                      ////////////////
>
>                      typedef boost::units::unit<lineal_force_dimension,lengths::ip_system> lineal_force_unit;
>
>              }
>
>              namespace si {
>
>                      ////////////////
>
>                      ////N/m, right?
>
> ////boost::units::force_dimension = newton
>
> ////boost::units::length_dimension = meter
>
>                      ////////////////
>
>                      typedef boost::units::unit<lineal_force_dimension,boost::units::si::system> lineal_force_unit;
>
>              }
>
>        }//lineal_force
>
> }//dimensional_analysis
>
> *.cpp-----------------------------------------------------
>
> //Imperial lb/in to SI N/m
>
> BOOST_UNITS_DEFINE_CONVERSION_FACTOR(
>
> dimensional_analysis::lineal_force::imperial::lineal_force_unit,
>
> dimensional_analysis::lineal_force::si::lineal_force_unit,
>
> double,
>
> 175.1268369864); // exact conversion
>
> BOOST_UNITS_DEFAULT_CONVERSION(
>
> dimensional_analysis::lineal_force::imperial::lineal_force_unit,
>
> dimensional_analysis::lineal_force::si::lineal_force_unit);
>
> //SI N/m to Imperial lb/in
>
> BOOST_UNITS_DEFINE_CONVERSION_FACTOR(
>
> dimensional_analysis::lineal_force::si::lineal_force_unit,
>
> dimensional_analysis::lineal_force::imperial::lineal_force_unit,
>
> double,
>
> 0.1837185501); // exact conversion
>
> BOOST_UNITS_DEFAULT_CONVERSION(
>
> dimensional_analysis::lineal_force::si::lineal_force_unit,
>
> dimensional_analysis::lineal_force::imperial::lineal_force_unit);
>
> //Imperial to SI.  This should convert lb/in to N/m and return 175.1268369864 (N/m)
>
> //But it does not.  Its converting lb (mass) to Kg (mass), 0.454
>
> const auto t2 = static_cast<boost::units::quantity<dimensional_analysis::lineal_force::si::lineal_force_unit>>(
>
> 1.0 * dimensional_analysis::lineal_force::imperial::lineal_force_unit::unit_type());
>
> //Again, Imperial to SI.  This should convert lb/in to N/m and return 175.1268369864 (N/m)
>
> //But it does not.  It returns lb (mass) to Kg (mass)
>
> const auto t3 = boost::units::conversion_factor(
>
> dimensional_analysis::lineal_force::imperial::lineal_force_unit::unit_type(),
>
> dimensional_analysis::lineal_force::si::lineal_force_unit::unit_type());
>
> //SI to Imperial.  This should convert N/m to lb/in and return 0.1837185501 (lb/in)
>
> //But it does not.  Its converting Kg (mass) to lb (mass), 2.205
>
> const auto t1 = static_cast<boost::units::quantity<dimensional_analysis::lineal_force::imperial::lineal_force_unit>>(
>
> 1.0 * dimensional_analysis::lineal_force::si::lineal_force_unit::unit_type());
>
> //So, I don?t know why the library is converting mass; I?ve tuned it to use boost::units::force_dimension/boost::units::length_dimension
>
> //I am doing something wrong where the library is not using force/length.
>
> //Below does work, mainly.
>
> //This is convert Si to SI and return value of 1.0 is correct.
>
> const auto t4 = static_cast<boost::units::quantity<dimensional_analysis::lineal_force::si::lineal_force_unit>>(
>
> 1.0 * boost::units::si::newton / boost::units::si::meter);
>
> //This convert lb/in to SI and return value is 175.1268369864 is correct.
>
> const auto t5 = static_cast<boost::units::quantity<dimensional_analysis::lineal_force::si::lineal_force_unit>>(
>
> 1.0 * boost::units::us::pound_force_base_unit::unit_type() / boost::units::us::inch_base_unit::unit_type());
>
> //This converts lb/in to lb/in and return value is of 1.0 is correct.
>
> const auto t6 = static_cast<boost::units::quantity<dimensional_analysis::lineal_force::imperial::lineal_force_unit>>(
>
> 1.0 * boost::units::us::pound_force_base_unit::unit_type() / boost::units::us::inch_base_unit::unit_type());
>
> //This is 2.205 and not correct.
>
> //It?s not converting SI-force/length to Imperial-force/length
>
> //Its converting Kg (mass) to lb (mass), 2.205
>
> const auto t7 = static_cast<boost::units::quantity<dimensional_analysis::lineal_force::imperial::lineal_force_unit>>(
>
> 1.0 * boost::units::si::newton / boost::units::si::meter);
>
> //What have I done wrong?
>
> //Any help is appreciated.
> _______________________________________________
> Boost-users mailing list
> Boost-users_at_[hidden]
> https://lists.boost.org/mailman/listinfo.cgi/boost-users

------------------------------

Message: 2
Date: Wed, 21 Nov 2018 15:55:35 +1300
From: Gavin Lambert <boost_at_[hidden]>
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] Program Options documentation is anaemic
Message-ID: <3ab79a24-e6ff-e311-1d12-adbe5646a123_at_[hidden]>
Content-Type: text/plain; charset=utf-8; format=flowed

On 20/11/2018 23:03, David Demelier wrote:
> Reading the type_value documentation from Boost Program options feels like:
>
>  ??? typed_value * composing();
>  ??? Specifies that the value is composing. See the 'is_composing'
> method for explanation.
>
> And the documentation of is_composing:
>
>  ??? bool is_composing() const;
>
> Not sure if I know more what this function is supposed to do now.

I agree that this seems somewhat unhelpful.

FWIW a quick look elsewhere found
https://www.boost.org/doc/libs/1_68_0/doc/html/program_options/tutorial.html#id-1.3.31.4.5
which describes that option in more detail -- specifically that it's
whether repeated parameters are merged or just replace the older value.

> Also, I think this module/documentation should take a s/method/function/g.

"Method" is the more common name for a method within a class.

------------------------------

Message: 3
Date: Tue, 20 Nov 2018 19:58:27 -0700
From: Steven Watanabe <watanabesj_at_[hidden]>
To: Matt Vinson via Boost-users <boost-users_at_[hidden]>
Cc: matt.vinson_at_[hidden]
Subject: Re: [Boost-users] boost::units - converting from one
    derived_dimension to another across systems (imperial to metric)
Message-ID: <4f601999-f01c-0535-37a3-15e6e21d8331_at_[hidden]>
Content-Type: text/plain; charset=utf-8

AMDG

On 11/20/2018 06:46 PM, Matt Vinson via Boost-users wrote:
> <snip>
> <some reformatting to reduce line wrapping>
> *.h-----------------------------------------------------
>
> namespace dimensional_analysis {
>
> ????typedef length_base_dimension::dimension_type length_dimension;
> ????typedef mass_base_dimension::dimension_type mass_dimension;
>
> typedef make_system<inch_base_unit,pound_base_unit>::type ip_system;
>

This should be pound_force_base_unit.

> ? namespace lineal_force {
> ??? typedef mpl::divides<force_dimension,length_dimension>::type lineal_force_dimension;??????????
>
> ??? namespace imperial {
>
> ????? ////////////////
> ????? ////lb/in, right?
>
> ////boost::units::force_dimension =pound
> ////boost::units::length_dimension = in
> ????? ////////////////
> ????? typedef unit<lineal_force_dimension,lengths::ip_system> lineal_force_unit;

This unit is nonsensical because the ip_system
as written is unable to represent the lineal_force_dimension.
That this doesn't give a hard compiler error is
a bug in the library.  Once you fix ip_system,
the conversions should be right.

> ??? }
> ??? namespace si {
> ??? ////////////////
> ??? ////N/m, right?
>

Yep.

> ////boost::units::force_dimension = newton
> ////boost::units::length_dimension = meter
> ????? ////////////////
> ????? typedef unit<lineal_force_dimension,si::system> lineal_force_unit;
> ??? }
> ? }//lineal_force
> }//dimensional_analysis
>
> *.cpp-----------------------------------------------------
>
> //Imperiallb/in to SI N/m
>

The following conversion definitions are unnecessary and have no effect:

> BOOST_UNITS_DEFINE_CONVERSION_FACTOR(
> dimensional_analysis::lineal_force::imperial::lineal_force_unit,
> dimensional_analysis::lineal_force::si::lineal_force_unit,
> double,
> 175.1268369864); // exact conversion
>
> BOOST_UNITS_DEFAULT_CONVERSION(
> dimensional_analysis::lineal_force::imperial::lineal_force_unit,
> dimensional_analysis::lineal_force::si::lineal_force_unit);
>
> //SI N/mto Imperial lb/in
>
> BOOST_UNITS_DEFINE_CONVERSION_FACTOR(
> dimensional_analysis::lineal_force::si::lineal_force_unit,
> dimensional_analysis::lineal_force::imperial::lineal_force_unit,
> double,
> 0.1837185501); // exact conversion
>
> BOOST_UNITS_DEFAULT_CONVERSION(
> dimensional_analysis::lineal_force::si::lineal_force_unit,
> dimensional_analysis::lineal_force::imperial::lineal_force_unit);
>
> <snip>
>

In Christ,
Steven Watanabe

------------------------------

Message: 4
Date: Wed, 21 Nov 2018 04:09:11 +0100
From: Adam Wulkiewicz <adam.wulkiewicz_at_[hidden]>
To: Zhang Qun <zhangq.rhy_at_[hidden]>
Cc: boost-users_at_[hidden]
Subject: Re: [Boost-users] Enquiry on boost.geometry and
    intersection()
Message-ID: <9d3e335d-df1a-7627-af4f-a9d3fd8c22ff_at_[hidden]>
Content-Type: text/plain; charset="utf-8"; Format="flowed"

Please do not top-post.

Zhang Qun?wrote:
> Hi Adam
> I think I have figured it out. Because of the precision, the two
> polygons are not the same.
>
> That also explains that why sometimes the intersection() gives me two
> intersection points looking "exactly" the same but if you look at the
> double precision, they are actually two different points. In reality,
> these two points can be safely considered the same point. I can solve
> this by comparing the two points distance. However, sometimes also
> because of the precision, the intersection() does not even give me any
> intersection points especially when the line is right across the
> vertex of the polygon. How do I solve this kind of problem?

Could you paste the WKTs of geometries (with sufficient precision) [1]
and say what do you get and what do you expect?

[1] e.g. std::cout << std::setprecision(20) << bg::wkt(polygon) <<
std::endl;

Adam
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