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Subject: Re: [Boost-users] [boost::filesystem::path] removing components of a path
From: Michael Powell (mwpowellhtx_at_[hidden])
Date: 2019-03-07 20:05:12
On Thu, Mar 7, 2019 at 2:57 PM Sean Farrow via Boost-users
<boost-users_at_[hidden]> wrote:
>
>
>
> -----Original Message-----
> From: Boost-users <boost-users-bounces_at_[hidden]> On Behalf Of Michael Powell via Boost-users
> Sent: 07 March 2019 19:53
> To: boost-users_at_[hidden]
> Cc: Michael Powell <mwpowellhtx_at_[hidden]>
> Subject: Re: [Boost-users] [boost::filesystem::path] removing components of a path
>
> On Thu, Mar 7, 2019 at 2:49 PM Sean Farrow via Boost-users <boost-users_at_[hidden]> wrote:
> >
> > Hi all,
> >
> >
> >
> > Iâm revisiting boost::filesystem::path after not using it for a while and wondered whether there is a way to remove parts of a path deeper than a specific directory?
> >
> > By way of an example, assume I have the following path declared:
> >
> > boost::filesystem::path path =âd:\\test1\\test2\\test3.txtâ
> >
> > what I want to do is determine whether test2 exists as part of the path and if it does remove everything after and including the found part of the path, so in this case \\test2\\test3.txt would be removed.
> >
> > I could do it by converting the path to a string, but wondered whether boost::filesystem could do this natively in some way.
>
> Natively, or via the FS API?
> Via the fs API, this needs to be cross-platform.
Well, I asked, because you said natively. I thought that was the
point, FS exposes it generically.
> I do not have the API right in front of me, but couldn't you peel off the children nodes to their parents until you found whether the current node was the match?
> I could iterate the path, but wondered whether path has a method to ask whether part of a path exists?
You want it to be simpler than the FS API? Again, I do not have the
docs right in front of me. I would start there.
> I'm not positive, but I am pretty sure FS knows about relative v.
> absolute paths, in this regard, as well.
>
> > Any help appreciated.
> >
> > Kind regards
> >
> > Sean.
> >
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