[boost] Re: property access name "set" conflicts with std::set

From: jsiek_at_[hidden]
Date: 2000-01-28 00:12:18

Fair enough. Here's the result with g++ 2.96

set_test.cc:14: use of class template `template <_Key, _Compare,
_Alloc> class set' as expression

With the KAI 3.4b (EDG 2.41.2) it works fine. 
With MIPSpro 7.3 it dies with or without the #include <set> :(

Here's the example I used (without the #include <set> everything
is happy).

#include <set>
#include <iostream>

namespace boost {
  struct foo { };
  inline void set(foo*,foo) { 
    std::cout << "setting foo" << std::endl;
  }

}

template <class T>
inline void generic_foo(T* it, T t) {
  set(it,t);
}

int
main()
{
  boost::foo* x;
  generic_foo(x, *x);
  return 0;
}

Dave Abrahams writes:
 > > I'm not totally sure what the standard says about this...  from 3.3.7
 > > I think that the function name is suppose to hide the class name.
 > >
 > > However, with g++ 2.91.66, for this code:
 > 
 > <snip>
 > 
 > I am loathe to make concessions for any one (non-conformant) compiler, but I
 > am particularly reluctant to base any decisions on the behavior of such an
 > outdated compiler. Please try your tests with gcc 2.95.2. It has certainly
 > got some substantial C++ bugs, but is reputed to be very much advanced over
 > 2.91.xx.
 > 
 > Thanks,
 > Dave 
 > 
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