[boost] Re: new approach to smart ptrs -- no new()s is good news

From: Stephen C. Gilardi (squeegee_at_[hidden])
Date: 2000-01-31 00:05:36

>  > I think the test has to be "if (left == this && right == this)" or
>  > something equivalent.
>
>If you're talking about the circular list implementation, then the
>simple test should suffice.  If the list is unique, both left and right
>pointers point to this.  If the list has two members, both left and
>right point to the other member, in this case, the leftmost element is
>the rightmost as well - so if the leftmost disappears, so does the
>rightmost.
>
>Gavin

OK, I see it now.  Thanks.

--Steve