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From: Andrew D Jewell (ajewell_at_[hidden])
Date: 2000-03-13 10:25:51
>I believe this already works fine without adding new classes. In what way is
>const_scoped_ptr<X> superior to scoped_ptr<const X>?
class qualified_scoped_ptr {
T * operator -> () throw() { return p; }
const T * operator -> () const throw() { return p; }
}
class scoped_ptr {
T * operator -> () const throw() { return p; }
}
class X {
void f();
};
some_function()
{
const scoped_ptr<X> spx;
const qualified_scoped_ptr<X> qspx;
spx->f(); // OK
qspx->f(); // compile error (or warning) : non-const method on const object.
}
does that answer your question?
Andy Jewell
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