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From: Howard Hinnant (hinnant_at_[hidden])
Date: 2000-08-27 09:00:39

David Abrahams wrote on 8/26/2000 8:06 PM
>I wonder
>whether one can technically count on std::pair having a trivial dtor?

In general, no. Consider std::pair<std::string, int>.

John Maddock wrote on 8/27/2000 6:16 AM
>If this is a major concern and you want to be able to do compile time
>asserts and other stuff on this, then how about specialising
>boost::has_trivial_destructor etc? The principal down side is that it
>introduces a dependency (on type_traits) that you may well not want....

For completeness, this is pretty easy to do. Here's how it might look
for std::pair:

namespace boost

template <class T1, class T2>
struct has_trivial_destructor<std::pair<T1, T2> >
        static const bool value = has_trivial_destructor<T1>::value
                               && has_trivial_destructor<T2>::value;


Then you can write compile time asserts (however they are currently
spelled) to check your Cost base class(es).


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