
Boost : 
From: Daryle Walker (darylew_at_[hidden])
Date: 20010512 19:48:18
Could/should we have a version of the "div" function defined for rational
numbers? This would provide a dividend and remainder. (You can't use
operator% because operator/ gives an exact answer, not an integer cutoff.)
The function could be something like:
template < typename T >
std::pair< boost::rational<T>, boost::rational<T> >
div( boost::rational<T> dividend, boost::rational<T> divisor )
{
typedef boost::rational<T> rational_type;
rational_type const result = dividend / divisor;
return make_pair( rational_type(result.numerator() /
result.denominator()), rational_type(result.numerator() %
result.denominator(), result.denominator() );
}
 Daryle Walker Mac, Internet, and Video Game Junkie darylew AT mac DOT com
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