[boost] Re: Will Boost.Function add operator == to itself?

From: Thorsten Ottosen (nesotto_at_[hidden])
Date: 2003-10-15 08:09:30

Hi Doug,

I havn't thought this through, but just wanted to ask about it

> Comparison between boost::function  objects cannot be implemented "well",
and
> therefore will not be implemented. The typical semantics requested for f
== g
> given boost::function objects f and g are:
>
>     * If f and g store function objects of the same type, use that type's
> operator== to compare them.
>     * If f and g store function objects of different types, return false.
>
> The problem occurs when the type of the function objects stored by both f
and
> g doesn't have an operator==:.

It seems to me that the problem only amounts to typeid( f1 ) == typeid( f2 )