|
|
Boost : |
From: David Abrahams (dave_at_[hidden])
Date: 2003-12-11 17:45:49
Sorry about this one. The docs say,
If "t" is an instance of T, then add_pointer<T>::type is the type
returned by "&t". For example "int" and "int&" both become "int*".
What about overloaded operator& ??
-- Dave Abrahams Boost Consulting www.boost-consulting.com
Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk