From: David Abrahams (dave_at_[hidden])
Date: 2003-12-11 17:45:49
Sorry about this one. The docs say,
If "t" is an instance of T, then add_pointer<T>::type is the type
returned by "&t". For example "int" and "int&" both become "int*".
What about overloaded operator& ??
-- Dave Abrahams Boost Consulting www.boost-consulting.com
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