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From: John Maddock (john_at_[hidden])
Date: 2003-12-13 07:57:11

> Sorry about this one. The docs say,
> If "t" is an instance of T, then add_pointer<T>::type is the type
> returned by "&t". For example "int" and "int&" both become "int*".
> What about overloaded operator& ??

Yep, changed to match the TR: A type that is the same as
remove_reference<T>::type* if T is a reference type, otherwise T*. For
example "int" and "int&" both become "int*".


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