Re: [boost] boost random question

From: Jens Maurer (Jens.Maurer_at_[hidden])
Date: 2004-02-13 17:11:16

Neal D. Becker wrote:
> For the new random number generators, if I want to share a single underlying
> uniform random generator, I need to do like so:
>  
>   typedef boost::mt19937 rng_t;
>   rng_t rng;
>  boost::variate_generator<rng_t&, boost::normal_distribution<> > tn (rng,        
> boost::normal_distribution<> (0, sqrt (var)));
>   boost::variate_generator<rng_t&, boost::pnseq_generator<1> > pn (rng,
> boost::pnseq_generator<1>());
> 
> That is, I need to say "rng_t&" for the 1st template param rather than
> "rng_t".  Is this correct?

Yes.

> The old rng lib passed the engine by ref in the constructor, but the new one
> doesn't.  Correct?

No.  The parameter in the constructor is what you put in the first
template parameter.  In your particular case, "rng" is passed by
reference.   (Btw, try "rng_t*" if you want to pass a pointer.)

Jens Maurer