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From: Peter Dimov (pdimov_at_[hidden])
Date: 2004-02-16 12:47:04

Andreas Huber wrote:
> Peter Dimov wrote:
>> Sean Kelly wrote:
>>> The user could delete the object passed to boost::thread with the
>>> existing design and there would be no provision for calling join.
>> I think that you are wrong. A boost::thread makes a copy of its
>> function object. The user can't delete it.
> I think he meant the object indirectly referenced by boost::function:
> MyActiveObject pActive = new MyActiveObject();
> boost::thread myThread( boost::function< void () >(
> boost::bind( &MyActiveObject::Run, pActive ) ) );
> delete pActive;

Why would anyone want to do that?

boost::thread myThread(
    boost::bind( &MyActiveObject::Run, MyActiveObject() )

Or if Run is renamed to operator():

boost::thread myThread( MyActiveObject() );

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