From: John Torjo (john.lists_at_[hidden])
Date: 2004-05-07 02:59:29
>I agree. IMO the best answer for now is to generate the 2^N overloads
>of operator() for some user-selectable N. Unary and binary functions
>are so common that IMO usually N==2 will do it.
I second that. Maybe n==3 anyone?
-- John Torjo Freelancer -- john_at_[hidden] -- http://www.torjo.com/logview/ - viewing/filtering logs is just too easy!
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