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From: Andreas Huber (ahd6974-spamgroupstrap_at_[hidden])
Date: 2005-03-03 13:16:48

Andreas Huber wrote:
>> I don't think of exiting a state as
>> destroying it, just that it's no longer "active" or whatever.
> Also, think of a state being
> represented by one bit. Zero means state is inactive, 1 means state
> is active. With state-local storage you can augment this one bit with
> whatever information you like.

Of course, this does not explain why the variables need to be
constructed on state entry and destructed on state-exit. So, in the
context of this discussion this is nonsense.

Andreas Huber
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