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From: David Abrahams (dave_at_[hidden])
Date: 2005-06-09 11:49:50

It seems to me that when BOOST_TYPEOF becomes available,
boost::result_of should use it in its default implementation,
something like:

  template <class F, class A>
  struct result_of<F(A)>
      typedef typename BOOST_TYPEOF(make<F>() ( make<A>() ) ) type;

Is that in the plan?

Dave Abrahams
Boost Consulting

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