Boost logo

Boost :

From: Neal Becker (ndbecker2_at_[hidden])
Date: 2006-05-25 15:33:16

STL iterators are designed so that ordinary pointers can be iterators. Can
we do the same with boost::range?

With STL we can do:
int x;
std::copy (&x, &x+1, output);

Does this work for range?

#include <boost/range.hpp>

template<typename in_t>
void F (in_t const& in) {
  typename boost::range_const_iterator<in_t>::type i = boost::begin (in);
  for (; i != boost::end (in); ++i) ;

int main() {
  int x;
  F (boost::sub_range<int*> (&x, &x+1));

usr/local/src/boost.cvs/boost/range/sub_range.hpp:26: instantiated from
‘boost::sub_range<int*>’ instantiated from here
/usr/local/src/boost.cvs/boost/range/mutable_iterator.hpp:37: error: ‘int*’
is not a class, struct, or union type

How do I turn the 'int x' into a 'range'?

Boost list run by bdawes at, gregod at, cpdaniel at, john at