Re: [boost] I'd like to write a static lambda library.

From: Atry (pop.atry_at_[hidden])
Date: 2007-06-27 06:23:09

It can not work now. But I will make expressions like
BOOST_STATIC_LAMBDA_FUNCTOR(_1 + _2) always worked for both native or
emulated typeof this week. Unfortunately, BOOST_STATIC_LAMBDA_FUNCTOR(_1 +
_2 * _1)::static_invoke(custom_value1, custom_value2) will never work if
result of custom_value2*custom_value1 or
custom_value1+custom_value2*custom_value1 is a unregistered type for the
platform does not have native typeof. The client not have native typeof have
to register all type may be evaluated is registered.

On 6/27/07, Alexander Nasonov <alnsn_at_[hidden]> wrote:
>
> Atry wrote:
> > Alexander Nasonov wrote:
> > Yes, getting a static function pointer is easy, I will add that method
> > later. But I have highly depended on typeof, I use typeof to determine
> > the result of almost all expressions, and Boost.Lambda does not. Typeof
> > enhanced lots of flexibility. For example, if a operator is overrided to
> > return a unusual return value, for Boost.Lambda, you have to manually
> > specify that return value using a "ret<return_type>(expr)" syntax. And I
> > used typeof to avoid that.
>
> I agree that typeof is a very powerful tool but it's still non-standard.
> Would it work if you enhance Boost.Lambda without using non-standard
> extensions and then apply BOOST_TYPEOF in your _client_ code?
>
> --
> Alexander Nasonov
> http://nasonov.blogspot.com
>
> Error of opinion may be tolerated where reason is left free to
> combat it. -- Thomas Jefferson --
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