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From: Alexander Nasonov (alnsn_at_[hidden])
Date: 2007-08-22 13:24:39

Alexander Nasonov <alnsn <at> yandex.ru> writes:

> Function type if better:
>
> int& (*result_tag)() = 0;
> typedef result_of<BOOST_TYPEOF(result_tag)>::result_type result_type;

Actually, this contruct has a limitation too. In some cases, typename
is required:

template<class T>
void foo()
{
  T& (*function_tag)() = 0;
  typedef typename remove_reference<BOOST_TYPEOF(function_tag)>::type sig;
} 

--
Alexander
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