Re: [boost] [xpressive] regex_replace() issue.

From: Robert Dailey (rcdailey_at_[hidden])
Date: 2008-03-14 14:01:18

On Fri, Mar 14, 2008 at 12:42 PM, Eric Niebler <eric_at_[hidden]>
wrote:

> Robert Dailey wrote:
> > An example of a string that I'll be searching is below:
> >
> > "This string $(variable1) has localized $(var2) text interleaved for no
> > $(reason)"
> >
> > In the string above, we have 3 variables. Each variable will reference a
> > string in a localization table, which will then be used to replace the
> > variable itself.
>
> It's not be hard to build such a thing using using regex_iterator.
> Here's some code to get you going...
>
> #include <map>
> #include <iostream>
> #include <boost/xpressive/xpressive.hpp>
> using namespace boost;

> <snip>
>
> HTH,
>
> --
> Eric Niebler
> Boost Consulting
> www.boost-consulting.com

Thank you very much for helping. I wouldn't go as far as to say it isn't
hard, because that looks very hard IMHO. I was hoping for something a little
more intuitive and built-in. Instead of going through all of that work I
will probably first try to find a different third party regular expression
library that can automate this task for me so that I can keep my code a
little cleaner and focus on the actual task. I know that other regex
libraries in other languages provide such a feature. Perhaps in the future
Boost.Xpressive can be extended to provide this behavior. You could simply
create a version of regex_replace() that takes a functor as the replacement
instead of a string.

Again, I appreciate the help and I will use your code example as a reference
in the future if I ever decide to come back to this.