From: David Abrahams (dave_at_[hidden])
Date: 2008-07-11 11:41:02
on Fri Jul 11 2008, "Robert Jones" <robertgbjones-AT-gmail.com> wrote:
> Is it possible to invoke user defined streaming operators within boost
> functions? In this style
> #include <iostream>
> #include <map>
> #include "boost/lambda/lambda.hpp"
> using namespace std;
> ostream & operator << ( ostream & ostrm, pair<string, string> const & input
> ostream & operator << ( ostream & ostrm, map<string, string> & inputs )
> using namespace boost :: lambda;
> for_each ( inputs.begin( ), inputs.end( ), ostrm << _1 << '\n' );
> return ostrm;
Yes, something like that works.
> Is this basically undoable, or am I doing it wrong?
Why would you think either one was true?
Note that std::endl can cause you big troouble, but since you're using
'\n' above I don't see a reason to worry. You do need something like
"using namespace boost::lambda;" to make "_1" valid, though.
> Also, does the online Comeau compiler understand the boost include
That's a question for Comeau.
-- Dave Abrahams BoostPro Computing http://www.boostpro.com
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