Re: [boost] [xint] Unary operator+

Subject: Re: [boost] [xint] Unary operator+
From: Chad Nelson (chad.thecomfychair_at_[hidden])
Date: 2010-05-05 15:18:33

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On 05/05/2010 01:37 PM, DE wrote:

>>>>> Um, because that operator is used for i + j and returns the sum,
>>>>> right?  Did I miss something?
>>>>
>>>> I suspect you (Robert) might be looking at the unary + operator...
>>>
>>> Doh!  So I was.  I didn't even look at the argument list when I saw
>>> it because I've never overloaded the unary +!
> 
>> I don't know anyone who does, but I assume that someone out there,
>> someone will, and would be irritated if it didn't work the same as the
>> built in integer types.
> 
> that person is me definitly

I was just wishing, when I wrote that, that I did know someone who did
that... purely out of curiosity, I wanted to ask why they (i.e. you) did
that? Is it just to make it more obvious that it's supposed to be a
positive number instead of a negative one?
- -- 
Chad Nelson
Oak Circle Software, Inc.
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