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From: Glen Fernandes (glen.fernandes_at_[hidden])
Date: 2020-01-29 05:32:44

On Wed, Jan 29, 2020 at 12:27 AM Gavin Lambert via Boost
<boost_at_[hidden]> wrote:

> claims that it returns a std::unique_ptr<T[], D>.


A std::unique_ptr<T[], D> stores a D::pointer.

In our case, D is alloc_deleter<T[], A> and its ::pointer is an
alloc_ptr<T[], Allocator>.

This alloc_ptr<T[], Allocator> stores an A::pointer and a size_t.

> This seems incompatible with what you're saying above.

It isn't.

> (There is also no mention of ptr() or size() there.)

It specifies that the ::pointer is an 'unspecified' pointer-like type.
I forgot to document that on this unspecified pointer type one can use
.ptr() to get the Allocator::pointer and .size() to get the size.


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