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From: Robert Ramey (ramey_at_[hidden])
Date: 2005-11-17 13:54:11

The problem is given something like +/inf how do I create a float with that value?

Can I use something like this?

double x;
x = std::numeric_limits<T>::quiet_NaN();

assert(x == std::numeric_limits<T>::quiet_NaN());

Robert Ramey

"Caleb Epstein" <caleb.epstein_at_[hidden]> wrote in message
  On 11/17/05, Kevin Wheatley <hxpro_at_[hidden]> wrote:

    don't know of a great solution but under IEEE class floats can't you
    compute the numbers...

    NaN = 0/0
    +inf = +1/0
    -inf = -1/0
    +0 = 0/+1
    -0 = 0/-1

  The +/-0 formulas work, but not the NaN and +/-Inf ones (divide by zero generates a floating point exception). Thankfully, can't we use numeric_limits for some of these?




  Caleb Epstein
  caleb dot epstein at gmail dot com


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