lambda library: how to use io manipulators?

From: Chuck Messenger (yg-boost-users_at_[hidden])
Date: 2003-05-16 13:36:02

The following compiles:

     (cout << _1 << "\n")(x);

but this doesn't:

     (cout << _1 << endl)(x);

(gcc 3.2.2)

I can't figure out how to use an io manipulator within a lambda function.

Firstly, how do I do it?  (e.g. suppose I want to use flush, for which 
there is no workaround like using "\n").

Secondly, a suggestion: it would be nice if support was built in for the 
io manipulators.

     - Chuck