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From: Cheenu Srinivasan (cheenu_srinivasan_at_[hidden])
Date: 2004-02-01 14:09:51
Duane Murphy wrote:
> The return type of boost::bind is fairly indeterminate. In order to call
> a bound function at a later time, look at boost::function. It does a nice
> job of holding on to a function that uses boost::bind.
I looked at "Using bind with Boost.Function" in the boost::function docs.
Mimicing that, for my example, I tried:
boost::function<double (int)> bound_func = boost::bind(f, _1, 1.234);
int i = 99;
cout << bound_func(i) << endl;
but it throws a bad_function_call exception when bound_func(i) is invoked.
How do I use boost::function for this situation?
Thanks.
Cheenu
I wrote:
> >I wish to store the return value of boost::bind in an intermediate object
> >to invoke it at a later time. I only ever see examples which combine
> >the call to boost:bind with the immediate invocation on the returned
> >object such as:
> >
> > #include <boost/bind.hpp>
> > using namespace boost;
> > #include <iostream>
> > using namespace std;
> >
> > double f(int i, double d) {
> > cout << "int = " << i << endl;
> > return d;
> > }
> >
> > main() {
> > int i = 99;
> > cout << bind(f, _1, 1.234)(i) << endl;
> > }
> >
> >Instead I'd like to postpone the call to the returned object. What's the
> >type of obj?
> >
> > main() {
> > int i = 99;
> > WHAT_IS_MY_TYPE obj = bind(f, _1, 1.234);
> > ...
> > cout << obj(i) << endl;
> > }
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