Re: [Boost-users] return type of boost::bind

From: Peter Dimov (pdimov_at_[hidden])
Date: 2004-02-01 15:31:42

Cheenu Srinivasan wrote:
> Duane Murphy wrote:
>> The return type of boost::bind is fairly indeterminate. In order to
>> call a bound function at a later time, look at boost::function. It
>> does a nice job of holding on to a function that uses boost::bind.
> 
> I looked at "Using bind with Boost.Function" in the boost::function
> docs. Mimicing that, for my example, I tried:
> 
>   boost::function<double (int)> bound_func = boost::bind(f, _1, 1.234);
>   int i = 99;
>   cout << bound_func(i) << endl;
> 
> but it throws a bad_function_call exception when bound_func(i) is
> invoked. How do I use boost::function for this situation?

Works for me; it's probably a compiler bug. Which compiler are you using?

Try

boost::function<double (int)> bound_func( boost::bind(f, _1, 1.234) );

instead.