[Boost-users] Re: [Regex] How to match the "End of buffer"/"End ofstring"?

From: jordi (jordil2_at_[hidden])
Date: 2005-01-03 12:05:13

John Maddock wrote:
>> I'm new in regex and this is my first post, so maybe the solution is 
>> obvious
>> but I couldn't find it in google...
>>
>> I need to parse the multiline output of a command, every line ends 
>> with a \n
>> except the last one, which actually it ends with the end of buffe ("\0"
>> character).  The output I need to parse is something like:
>>
>>   "text1 this is a multiple-word text\n
>>   text2 another text"
>> (the second line does not have a newline)
>>
>> As a result I want only two sub-expression in a line using a regex like:
>>
>> (\w+)\s+([^\n]+)\n
>>
>> The first submatch should be the first word ("text1" and "text2"), 
>> while the
>> second submatch would be the rest of the line ("this is a multiple-word
>> text" and "another text")
>>
>> In my program I use regex_search with the boost::match_continuous option,
>> all the other regex objects are created with the default options.
> 
> 
> It depends whether you want to capture the newline character or not, if 
> you do then:
> 
> (\w+)\s+([^\n]+)(?:\n|$)
> 
> would do the trick, otherwise if you don't want the newline character 
> (just the contents of each whole line) then:
> 
> ^(\w+)\s+([^\n]+)$
> 
> Used without the match_continuous flag would do it.
> 
> John.
Thanks for your reply.

I will try...

Best regards,

Jordi