Re: [Boost-users] Exception when reading from an archive

From: kauai (kauai_diver_at_[hidden])
Date: 2005-05-04 19:17:15

--- Eyal Susser <eyal.susser_at_[hidden]> wrote:
> Hi,
> I'm using the serialization library, but have encountered
> problems.
> 
> I have an archiver that I use with a stringstream to
> serialize
> objects.  I write some ints to the archive using "ar <<
> my_int", and
> finally I archive a derived class wi ar << derived.  So
> far, so good.
> 
> In a different process, I create an input archiver, read
> the integers,
> and then pass the archiver to a different method, where I
> create an
> instance of the class I serialized and use "ar >>
> instance".  This
> throws an exception.
> 
> The code for the object created is one *.so, and teh code
> that does
> the creating does it with a templated class factory in a
> different
> *.so.  Is that why I'm gettin the exceptions?  Is there a
> solution?
> 
> The exception is boost::archive::archive_exception
> what():  stream error.
> 
> Thanks.
> 
> _______________________________________________
> Boost-users mailing list
> Boost-users_at_[hidden]
> http://lists.boost.org/mailman/listinfo.cgi/boost-users
> 

Are you registering all your classes you are serializing?
Your input archiver may not know about all class types in
your archive.

Use the macro BOOST_CLASS_EXPORT(ClassName) to export a
GUID for every class. This should be in a .cpp file outside
of any functions.  include <boost/serialization/export.hpp>
to use it.  This include should be placed after any
archiver includes.

Also within your class (if it is a container for other
classes) you will need to do this in your serialize
function:
        ar.register_type(static_cast<ClassName*>(NULL)); 
// if they are pointers

Have fun,
-K

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