Boost Users :
From: Zeljko Vrba (zvrba_at_[hidden])
Date: 2005-08-05 00:56:55
David Abrahams wrote:
> However, reliably taking the address of an overloaded function
> involves knowing the exact types in its signature. I'm not sure how
> you can do that.
I have googled a bit and found the following example in the Microsoft
C++ reference: http://tinyurl.com/cljnn
int Func( int i, int j );
int Func( long l );
int (*pFunc) ( int, int ) = Func;
Do you see any problems with this?
I guess it should be possible to take an address of an operator by
replacing 'Func' with e.g. 'operator<'. I'll try it and report the result.
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