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From: James E Taylor (james_at_[hidden])
Date: 2005-08-17 10:19:01
I hope this isn't a stupid question, but....
Is the boost mutex constructor thread-safe?
I am writing a singleton template and trying to avoid the static initialisation/destruction order fiasco.
I envisage two threads accessing a function like this concurrently:
template<typename T>
boost::shared_ptr<T>
my_func()
{
static boost::mutex m;
boost::mutex::scoped_lock l(m);
static boost::shared_ptr<T> p(new T);
return p;
}
and my worry is that both threads could attempt to do the static initialisation of m concurrently. Is there protection against this? Is it even possible to protect against this?
I've tried to use boost::call_once, which would give sufficient guarantees but it's quite inflexible as nothing can be passed to or from the function being called.
I know that integral types (like a pthread_t) of static storage are initialised before main() and before constructors of statically allocated objects are called, which means there would be no problem using a pthread_t above. However, constructors of objects of static storage are called at a time when there could be multiple threads running.
Am I worrying about nothing? Or is there a problem here?
Thanks,
James
-- James E Taylor ___________________________________ NOCC, http://nocc.sourceforge.net
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