Re: [Boost-users] boost::sub_range vs boost::iterator_range

From: Thorsten Ottosen (tottosen_at_[hidden])
Date: 2005-12-08 18:18:55

Victor A. Wagner Jr. wrote:

>>I've added the following overload
>>
>>
>>         sub_range& operator=( sub_range r )
>>         {
>>             //
>>             // argument passed by value to avoid
>>             // const_iterator to iterator conversion
>>             //
>>             base::operator=( r );
>>             return *this;
>>         }
>>
>>and can now compile your program.
>>
>>I've also committed this to the main cvs.
> 
> 
> yes, it compiles, and runs on vc7.1
> it does NOT compile on vs8.0 (which is currently my default compiler)

was there any difference in the compiler there? Is it still operator= in 
iterator_range that gets called?

-Thorsten