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From: Eric Niebler (eric_at_[hidden])
Date: 2006-01-16 17:07:58


Thorsten Ottosen wrote:
> Eric Niebler wrote:
>> Thorsten Ottosen wrote:
>>
>>> as_mutable();
>>>
>>> The latter would be a cast from rvalue to lvalue like it happens in
>>> boost.foreach.
>>
>> Not sure what you're referring to. Boost.Foreach does no such
>> rvalue-to-lvalue cast.
>
> So this wouldn't compile:
>
> vector<int> foo();
> ...
> BOOST_FOREACH( int& r, foo() )
> ++r
>
> ?

No, it doesn't compile, and it shouldn't. What would be the point of
mutating the unnamed temporary vector returned by foo()?

-- 
Eric Niebler
Boost Consulting
www.boost-consulting.com

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