Boost Users :
From: Andy Little (andy_at_[hidden])
Date: 2006-01-20 12:23:22
"Merrill Cornish" wrote
> I _think_ I may know why concatenation is working like it is.
> I believe the purpose of the ## concatentation operator is to
> cause one symbol (i.e., letters, numbers, underscore) to be
> created out of two symbols. Since the result of the concatenation
> that you specified is _not_ a legal symbol, the preprocessor
> appears to have made a best guess at what should be done
> rather than flag an error.
'pp-number e sign' is a valid pre-processing sequence isnt it?.
Its pretty cruel whatever it is. :-(
I will try posing the question on comp.std.c++.
If any one has a workaround for it I'd be interested to hear it.
Thank for the input
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