Re: [Boost-users] [function] How do you bind two boost::functionobjects together?

From: Jason House (jasonhouse_at_[hidden])
Date: 2006-10-01 23:52:47

Sohail Somani wrote:
>>-----Original Message-----
>>From: boost-users-bounces_at_[hidden] 
>>[mailto:boost-users-bounces_at_[hidden]] On Behalf Of Jason House
>>
>>I want the result of the bound expression to have one input parameter 
>>that would be decided later.  For instance:
>>
>>bool some_function(char x);
>>boost::function<bool (char) some_function_object(some_function);
>>boost::function<bool (int)> f = convert(some_function_object)
>>std::cout << f(32);
> 
> 
> I think what you're looking for is composition of functions? i.e. g o f
> (x) => g(f(x))?
> 
> The right nomenclature might help... What it seems you want to do is to
> generate a function that does this:
> 
> bool the_result(int i)
> {
> 	return some_function(convert_to_char(int));
> }
> 
> Is that right?
> 
> I know you can curry with boost function + lambda but I haven't tried
> composition myself (though it should be possible!)

Yes, you're right.

It seems that my mistake was possibly that I was using 
boost::lambda::bind instead of boost::bind.