Re: [Boost-users] [bind] how to get a funtor of a function since the function's template argument is a functor

From: Peter Dimov (pdimov_at_[hidden])
Date: 2007-02-03 15:56:43

hongleij_at_[hidden] wrote:
> #include <boost/bind.hpp>
> #include <boost/thread.hpp>
>
> #include <iostream>
>
>
> class BufferMoniter
> {
> public:
>   void maitain()
>   {
>      std::cout <<" BufferMoniter" << std::endl;
>   }
> };
> class LocalPeer
> {
> public:
>   template <class T>
>   void caller(unsigned int interval,T t)
>   {
>       //do something
>       t();
>   }
>  void fork()
>  {
>      BufferMoniter *pBuffer=new BufferMoniter( );
>      boost::thread
>  thrd(caller(500,boost::bind(&BufferMoniter::maitain,pBuffer)) ; //
> that i really want.a fuctor of
> caller(500,boost::bind(&BufferMoniter::maitain,pBuffer).
>
>      thre.join();
>  }

The easiest way is to use boost::function<void()> to hide the type of T. 
This will also take care of one additional problem with interpreting the 
inner bind as a nested subexpression.

   void caller(unsigned int interval, boost::function<void()> const & t)
   {
       //do something
       t();
   }

  void fork()
  {
      shared_ptr<BufferMoniter> pBuffer( new BufferMoniter() ); // take care 
of leak
      boost::function<void()> f = 
boost::bind(&BufferMoniter::maitain,pBuffer);
      boost::thread thrd( boost::bind( caller, 500, f ) );

      thrd.join();
  }