Re: [Boost-users] lambda usage

From: ka (filip.konvicka_at_[hidden])
Date: 2007-03-14 12:31:22

Hi Yu,

I happen to have finished reading lambda docs just a while ago... :-)

std::cout << (_1 + _2)(boost::lambda::make_const(10), 
boost::lambda::make_const(10));
std::cout << std::endl;

does the job. You have to be careful about passing constants as 
arguments, see docs for details. As for std::endl, the problem is that 
the resulting value (result of std::cout << _lambda_expression_) has 
some special type. There are some workarounds, try googling on that if 
this worries you.

Cheers,
Filip

> Hi,
>
> It seems that the lambda manual lacks of a simple working example.
>
> I'm made up the following example. But it's not working. Could you
> please show me how to make it work?
>
> Thanks,
> Peng
>
> #include <boost/lambda/lambda.hpp>
> #include <boost/lambda/core.hpp>
> #include <iostream>
>
> using namespace boost::lambda;
>
> int main() {
>   std::cout << (_1 + _2)(10, 10) << std::endl;
> }
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> Boost-users mailing list
> Boost-users_at_[hidden]
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>   

-- 
Filip Konvic(ka
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