Re: [Boost-users] [regex] How to compile with desired version when multiple versions of boost library are installed

From: Chandan Nilange (chandan_nilange_at_[hidden])
Date: 2007-07-16 01:02:54

Hello,

I have boost_1_32 version installed at
/usr/include/boost
Also, I have installed boost_1_34 at another
path:/home/myname/work/boost/boost_1_34_0/

Now when I try to run with 1_34 version, it still
points to 1_32 version at /usr/include (this is
observed when I debug using gdb it refers to
/usr/include/boost/regex/v4/match_results.hpp:118)

I tried following things:

1]
export
LD_LIBRARY_PATH=/home/myname/work/boost/boost_1_34_0/boost:$LD_LIBRARY_PATH
export
PATH=/home/myname/work/boost/boost_1_34_0/boost:$PATH

2]
I am using following command for compilation
g++ -c -g -I/home/myname/work/boost/boost_1_34_0/boost
${TEST_FILES_PATH}/${TEST}.c
g++  ${TEST}.o  -L/home/myname/work/boost/lib
-lboost_regex

3] I am including boost header in ${TEST}.c as below
#include "boost/regex.hpp"

Any help is most welcome.

Thanks and Regards,
Chandan

       
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