Re: [Boost-users] [boost][lexical_cast] simple example doesn't work with vector<T>

From: Ovanes Markarian (om_boost_at_[hidden])
Date: 2008-04-07 14:30:18

Just an addition:

Explicit specialization of std templates is legal. So if you _exactly_ know
vector types for which your <<-operator should work you can write:

namespace std
{
  template<>
  ostream& operator<< (ostream& os, const vector<MyTypeX>& v)
  {
    copy(v.begin(), v.end(), ostream_iterator<T>(os, ";"));
    return os;
  }
}

By the way there was a big discussion about this on std list and I fluently
read the upcoming Standard draft and saw that this paragraph changed. I not
any longer sure if this will be allowed with the new standard.

Best Regards,
Ovanes

On Mon, Apr 7, 2008 at 8:14 PM, Steven Watanabe <watanabesj_at_[hidden]>
wrote:

> AMDG
>
> Scott McMurray wrote:
> > On Sun, Apr 6, 2008 at 5:15 PM, Andy Stevenson
> > <andy.stevenson_at_[hidden]> wrote:
> >
> >> Why doesn't the lexical_cast work below?
> >>
> >>
> >
> > Your operator<<'s not in namespace std, so ADL cannot find it.
> >
> > ( I think that's it, anyways. )
>
> Yes.  It isn't legal to put it in namespace std, though.
>
> In Christ,
> Steven Watanabe
>
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