Re: [Boost-users] [thread] how to use thread::timed_join

From: Patrick Loney (Patrick.Loney_at_[hidden])
Date: 2008-04-17 07:08:10

Not tested but there must be other ways of doing it like:

Typedef Btime = boost::posix_time;
Typedef Bperiod = Btime::time_duration;

thr.timed_join(Bperiod (0,0,0, Btime::millisec( 100 ) ) );

perhaps even 

thr.timed_join(Btime::millisec( 100 ) );

or 

thr.timed_join(Bperiod (0,0,0, 100 ) );

As this is a cross platform library ticks_per_second should not be required.

-----Original Message-----
From: boost-users-bounces_at_[hidden] [mailto:boost-users-bounces_at_[hidden]] On Behalf Of Johan Råde
Sent: 17 April 2008 11:47
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] [thread] how to use thread::timed_join

Johan Råde wrote:
> I want to do a timed join, with  a relative time of 0.1s.
> I can not figure out from the docs how to do this.
> I find the prototypes somewhat mystifying:
> 
>      bool timed_join(const system_time& wait_until);
> 
>      template<typename TimeDuration> bool timed_join(TimeDuration const& rel_time);
> 
> What is system_time?
> What should TimeDuration be?
> 
> I'm using Windows.
> 
> Thank you,
> Johan Råde

I figured out the answer myself:

        int n = (int)boost::posix_time::time_duration::ticks_per_second() / 10;
        boost::posix_time::time_duration delay(0,0,0,n);
        thr.timed_join(delay);

I bit more complex than I had expected.

--Johan

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